Consider the given equation.
Sum of the masses of the reactants (LHS) = Mass of 1H2 + Mass of 1H3
= 2.014102 + 3.01604 = 5.030151 u
Sum of the masses of the products (RHS) = Mass of 2He4 + Mass of 0n1
= 4.00388 + 1.00866 = 5.01254 u
Difference in masses = Δm = 5.030151 u – 5.01254 u = 0.17611 = 0.018 u
This much mass is converted to energy. Therefore,
Energy released ≈ Δ m × 931.5 = 0.018 × 931.5 = 16.8 MeV
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