admin May 31, 2021 A force of 1.5 × 104 causes a strain of 1.4 × 10-4 in a steel cable of cross-sectional area 4.8 × 10-4 m2. 2 Comments A force of 1.5 × 104 causes a strain of 1.4 × 10-4 in a steel cable of cross-sectional area 4.8 × 10-4 m2. Solution Given Force, F = 1.5 × 104 N Strain in length, ϵ = 1.4 × 10-4 Area, A = 4.8 × 10-4 m2 Required Young’s modulus, Y Energy per unit volume, E Now, Young’s modulus = stress/strain and stress = F/A, therefore, Y = (F/A)/ϵ. Put values, Strain energy, E = ½ (stress × strain). Put values, MCQs List of Questions Previous Question Post navigation Previous Previous post: Numerical Problem 5, Physics of SolidsNext Next post: Explanation of Hook’s law, Modulus of elasticity 2 Comments Pingback:Numerical Problem 5, Physics of Solids – msa Pingback:Numerical Problems on Physics of Solids – msa Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment Name * Email * Website Save my name, email, and website in this browser for the next time I comment.
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