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A force of 1.5 × 104 causes a strain of 1.4 × 10-4 in a steel cable of cross-sectional area 4.8 × 10-4 m2.

Solution

Given                    Force, F = 1.5 × 104 N                      

                             Strain in length, ϵ = 1.4 × 10-4

                              Area, A = 4.8 × 10-4 m2                   

Required             Young’s modulus, Y                    Energy per unit volume, E

  • Now, Young’s modulus = stress/strain and stress = F/A, therefore, Y = (F/A)/ϵ. Put values,
  • Strain energy, E = ½ (stress × strain). Put values,

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