Problem 2: The time period of a pendulum is measured to be 3 s in the inertial frame of the pendulum. What is the period when measured by an observer moving with a speed of 0.95 c with respect to the pendulum?
Solution
Formula:
We know that
Where t0 is the rest or proper time, t is the relativistic time, v is the relativistic velocity and c is the velocity of light.
Given:
Time period at rest = t0 = 3 s
Relativistic velocity = 0.95 c
Velocity of light = c = 3 × 108 m/s
Asked: Relativistic velocity timeperiod, t
Put values in the formula
Pingback:Numerical Problem 3, Advent of Modern Physics … msa – msa
Pingback:Numerical Problem 1, Advent of Modern Physics … msa – msa
Pingback:Numerical Problems, Advent of Modern Physics … msa – msa