Problem 7: For the same RLC series circuit having a 40.0 Ω resistor, 3.00 mH inductor and a 5.00 μF capacitor: (a) Find the resonant frequency (b) calculate Irms at resonance if Vrms is 120 V.
Solution
(a) Given
L = 3.0 mH = 3 × 10-3 H, C = 5.0 μF = 5.0 × 10-6F
Asked
Resonant frequency, fr.
Formula
Put the values
(b) Given
R = 40 Ω Vrms = 120 V
Asked: Irms
Formula
However in case of resonance, XL = XC, therefore,
Z = R =40 Ω
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