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Question 12: What is the angle for which the maximum height reached and corresponding range are equal?


We know that the range of a projectile is given by

Similarly, height of the projectile is

Now according to the condition of the question, both these distances are equal. Therefore,

Now sin2θ = 2sinθcosθ, so put in the above equation,

(Use calculator to find this.)

Therefore, for θ = 760, the range and height of the projectile will be equal.

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  1. Pingback:Conceptual Questions Forces and Motion, Physics 11 – msa

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