Question 12: What is the angle for which the maximum height reached and corresponding range are equal?
We know that the range of a projectile is given by
Similarly, height of the projectile is
Now according to the condition of the question, both these distances are equal. Therefore,
Now sin2θ = 2sinθcosθ, so put in the above equation,
(Use calculator to find this.)
Therefore, for θ = 760, the range and height of the projectile will be equal.