Angle of projection for which R = H … msa

Question 12: What is the angle for which the maximum height reached and corresponding range are equal?

Answer

We know that the range of a projectile is given by

Similarly, height of the projectile is

Now according to the condition of the question, both these distances are equal. Therefore,

Now sin2θ = 2sinθcosθ, so put in the above equation,

(Use calculator to find this.)

Therefore, for θ = 76⁰, the range and height of the projectile will be equal.