(b) Given the equation CH4 (g) + 2O2 (g) ——→ CO2 (g) + 2H2O (g) + Heat, how can this be read in terms of particles, moles and masses?
Solution
The given equation is CH4 (g) + 2O2 (g) ——→ CO2 (g) + 2H2O (g) + Heat.
This equation can be read in a number of ways;
In terms of particles
1 molecule of CH4 + 2 molecules of O2 ———-→ 1 molecule of CO2 + 2 molecules of H2O
Alternatively,
6.022 × 1023 molecules of CH4 + 2 × 6.022 × 1023 molecules of O2 ———-→ 6.022 × 1023 molecules of CO2 + 2 × 6.022 × 1023molecules of H2O
In terms of moles
Since 6.022 × 1023 molecules of CH4, Or O2 or CO2 is one mole, therefore,
1 mol of CH4 + 2 mol of O2 ———–→ 1 mol of CO2 + 2 mol of H2O
In terms of masses
Now one mol of CH4 is 16 g, 2 moles of O2 is 64 g, 1 mol of CO2 is 44 g and 2 moles of H2O is 36 g, therefore,
16 g of CH4 + 64 g of O2 ———-→ 44 g of CO2 + 36 g of H2O
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