Menu Close

Problem 1: What is the shortest wavelength photon emitted in the Lyman series of hydrogen?

Solution

The general equation for the wavelengths in the hydrogen spectrum is

In the Lyman series, the transition takes place in innermost orbit (P = 1) of the hydrogen atom. The equation for the wavelength emitted in such transition is

Where R is the Rydberg constant and equal to 1.0973732 × 107 m-1. For the shortest wavelength, n = ∞. Put values in the above equation,

Therefore,

2 Comments

  1. Pingback:Numerical Problems, Atomic Spectra … msa – msa

  2. Pingback:Wavelength of second line of Paschen series … msa – msa

Leave a Reply

Your email address will not be published. Required fields are marked *