Problem 1: In a Young’s double slit experiment the separation of the slits is 1 mm and red light of wavelength 620 nm is falling on it. Determine the distance between the central bight band and the fifth bright fringe on the screen which is 3 m away from the slit.

Solution

Given data

Separation of slits = d = 10^{-3}m Incident wavelength (red light) = λ = 620 × 10^{-9}m
No of bright fringes = m = 5 Distance in slits and screen = L = 3 m

Required

Distance between central band and 5^{th} fringe = Y =?

(Please note the perpendicular AD in the diagram is not that exact1)

Formula

Where Y is the distance between central point and 5th fringe which we want to find. Put the values,

Pingback:Numerical Problem 2, Physical Optics, Physics 11 … msa – msa

Pingback:Numerical Problems, Physical Optics, … msa – msa

Pingback:Numerical problems on Physical Optics, Physics 11 – msa