June 20, 2020 Calculate the length of a second pendulum having time period 2 seconds at a place where g = 9.8 m/d^2. 4 Comments Problem 4: Calculate the length of a second pendulum having time period 2 seconds at a place where g = 9.8 ms^{-2}. Answer Given data Time period = T = 2 s, g = 9.8 m/s^{2} Required Length = l =? Formula Put values Next Question List of Questions Previous Question Tagged Calculate the length of a second pendulum having time period 2 seconds at a place where g = 9.8 ms-2., Numerical Problem 4 on oscillation in the physics course of first year. Post navigation Previous Previous post: Numerical Problem 3 on Oscillation, Physics 11 … msaNext Next post: Numerical Problem 5, Oscillations, Physics 11 … msa 4 Comments Pingback:Numerical Problems on Oscillation, Physics 11 – msa Pingback:Numerical Problem 5, Oscillations, Physics 11 … msa – msa Pingback:Numerical Problem 3 on Oscillation, Physics 11 … msa – msa Pingback:numerical-problems-on-oscillation-physics-11-msa – msa Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment Name * Email * Website Save my name, email, and website in this browser for the next time I comment.

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