Consider the given equation.

Sum of the masses of the reactants (LHS) = Mass of _{1}H^{2} + Mass of _{1}H^{3}

= 2.014102 + 3.01604 = 5.030151 u

Sum of the masses of the products (RHS) = Mass of _{2}He^{4} + Mass of _{0}n^{1}

= 4.00388 + 1.00866 = 5.01254 u

Difference in masses = Δm = 5.030151 u – 5.01254 u = 0.17611 = 0.018 u

This much mass is converted to energy. Therefore,

Energy released ≈ Δ m × 931.5 = 0.018 × 931.5 =** 16.8 MeV**

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