- P.E at the surface of bridge = mgh = m× 9.8 × 10 = 98m jouls

P.E when it falls 5 meter = m × 9.8 × 5 = 49m jouls

Difference in P.E = K.E = 98m – 49m = 49m jouls. Therefore,

½ mv^{2} = 49m OR v^{2} = 2 × 49 = 98 OR v = √98 = 9.899 = **9.9 ms**^{-1}

Therefore, velocity of the body 5 m above the water surface is 9.9 ms^{-1}.

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