Now suppose, we have 4 mol of H2 and 3 mol of O2. When 4 mol of H2 and 3 mol of O2 are allowed to react, 4 mol of H2 will react with 2 mol of O2. There would be 1 mol of O2 in excess because the given amount of 4 mol of H2 has now been completely consumed. Therefore, the reaction will come to stop despite 1 more mol of O2 is available. Thus the product formation of H2O is limited by the amount of H2 present. Therefore, H2 is called limiting reagent.
Note: O2 is the reagent in excess in this case.
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