Menu Close

Short Questions on Stoichiometry

This page consists of solutions of short questions included in the Stoichiometry course of First Year.

Question No

Statement of the question

Question 1

What is gram atom? Why the concept of gram atom is useful in chemistry? See Answer

Question 2

The mass of 5 moles of an element X is 60 g. Calculate the molar mass of this element. Name the element.

See Answer

Question 3

Explain why balanced chemical equations are used in stoichiometric problems?

See Answer

Question 4

How will you identify the limiting reagent in a reaction?

See Answer

Question 5

Define molar volume of a gas. What will be the volume of 2.5 moles of H2 gas and 60 g NH3 at STP?

See Answer

Question 6

Why the actual yield is usually less than the theoretical yield of a reaction?

See Answer

Question 7

(a) What do you mean by percentage composition of a compound? How the percentage of an element is calculated in a compound?

 (b) Calculate the percentage composition of each of the following compounds. (Given atomic weights of the elements).

(i) MgSO4 (ii) C3H6O (iii) KMnO4 (iv) C6H6 (v) NaAl(SO4)2 (vi) CaCO3 (vii) CH4

[Mg = 24, S = 32, O = 16, C = 12, K = 39, Na = 23, Mn = 55, Ca = 40, Al = 27, H = 1]

See Answer

Question 8

(a) Differentiate between a “limiting reagent” and a “reagent in excess”. How will you identify the limiting reagent in a chemical reaction?

(b) How does a limiting reagent control the amount of the product formed? Give an example.

See Answer

Question 9

A technician weighs 40 g of sodium. How many moles of formula units are in the sample?

See Answer

6 Comments

  1. Pingback:Definition of gram atom and its importance in Chemistry … msa

  2. Pingback:Actual yield is less than theoretical yield … msa

  3. Pingback:Definition of molar volume … msa

  4. Pingback:MCQs, Stoichiometry, Chemistry 11 … msa

  5. Pingback:Stoichiometry, Long Questions

  6. Pingback:chemistry-11 – msa

Leave a Reply

Your email address will not be published. Required fields are marked *