Where E is the energy, f is the frequency of oscillator and ‘h’ is Planck’s constant. To find the dimensions of h, therefore, we have to find the dimensions f E and f. Now, joul is the unit of energy, the dimensions of energy can be calculated as

Dimensions of energy = [J] =[N m] = [kg ms^{-2 }m] = [kg m^{2} s^{-2}]

⇒ Dimensions of energy = [M][L^{2}][T^{-2}] = [ML^{2}T^{-2}] ….. (A)

Similarly, dimensions of frequency, f = [T^{-1}] ….. (B)

Now to find the dimensions of Planck’s constant, h, we divide the dimensions of energy on the dimensions of frequency.

Dimensions of ‘h’ = [ML^{2}T^{-2}]/[T^{-1}] = [ML^{2}T^{-1}]

There is a mistake in numerical 6 part à in the last step

Yes, thanks Faizan. T is raised to power -1. Now it is corrected. Thanks once again.

Very very thankful 💞

Muhammad Abid

Your are welcome.

thanks

thankssssssssssssssssssssssssss

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