Question 1: Evaluate the following functions:
Solution
a. 
Applying sum rule of limits,
= 4 – 6 – 7 = -9 Answer
b. 
By product rule,
= (3 + 5)(2×3 – 7) = 8(6 – 7) = -8 Answer.
c. 
d. 
e. 
Apply power rule,
f. 
When x → 1, the limit of the function is of the form 0/0, which is undefined. So, first we rationalize the function.
Multiplying by 
, we get,
Answer
g. 
When x → 0, the function is of the form 0/0 which is undefined. Therefore, simplifying,
h.
When x→1, the function is of the form 0/0. So, simplifying, 
i. 
j. 
When x→0, the given function is 0/0 (undefined). Therefore, simplifying,
k. 
As sec 0° = 1, the function is undefined when x→0. Simplifying,
l. 
The given equation is of the form 0/0.
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