admin January 7, 2022 Math's 12, Ex 1.4, Question 1 1 Comment Question 1: Evaluate the following functions: Solution a. Applying sum rule of limits,= 4 – 6 – 7 = -9 Answer b. By product rule,= (3 + 5)(2×3 – 7) = 8(6 – 7) = -8 Answer. c. d. e. Apply power rule, f. When x → 1, the limit of the function is of the form 0/0, which is undefined. So, first we rationalize the function.Multiplying by , we get, Answer g. When x → 0, the function is of the form 0/0 which is undefined. Therefore, simplifying, h.When x→1, the function is of the form 0/0. So, simplifying, i. j. When x→0, the given function is 0/0 (undefined). Therefore, simplifying, k. As sec 0° = 1, the function is undefined when x→0. Simplifying, l. The given equation is of the form 0/0. Post navigation Previous Previous post: Math’s 12, Exercise 2.1, Question 3Next Next post: Math’s 12, Exercise 1.4, Question 2 1 Comment Pingback:Math’s 12, Exercise 1.4 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment Name * Email * Website Save my name, email, and website in this browser for the next time I comment.

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