admin January 6, 2022 Math's 12 Ex 2.1 Question 3 1 Comment Question 3: A ball is thrown straight up. Its height after t seconds is given by the formula h = -16t^{2}+80t. Find the average velocity for the specified intervals. Solution Let h(t) = -16t^{2} + 80tThen h(t+Δt) = -16(t + Δt)^{2} + 80(t + Δt)Cancelling Δt,Now t = 2 and Δt = 2.1 – 2 = 0.1, therefore, Next Question List of Questions Previous Question Post navigation Previous Previous post: Math’s 12, Exercise 2.1, Question 2 … msaNext Next post: Math’s 12, Exercise 1.4, Question 1 1 Comment Pingback:Math’s 12, Exercise 2.1 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment Name * Email * Website Save my name, email, and website in this browser for the next time I comment.

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