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Question 3: A ball is thrown straight up. Its height after t seconds is given by the formula h = -16t2+80t. Find the average velocity for the specified intervals.

Solution

Let h(t) = -16t2 + 80t
Then h(t+Δt) = -16(t + Δt)2 + 80(t + Δt)


Cancelling Δt,


Now t = 2 and Δt = 2.1 – 2 = 0.1, therefore,

 

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