Consider the diagram above. Let V_{x} is the velocity of the bus and V_{y} is the velocity with which the ball is thrown. We choose a scale such that 1 cm = 10 m/s. Therefore,

V_{x} = 2.5 cm = AB and V_{y} = 1.25 cm (approximately) = BC

By head-to-tail rule of vector addition, the resultant velocity is AC = 2.773 cm

Convert back the vector to velocity, 2.773 × 10 = 27.73 ≅ 28 m/s

To find the direction, apply Pythagoras theorem to the right-angled triangle,

Very nice answer

Israel MohmandThank you very much.

Pingback:Numerical Problem 2, Vectors and Equilibrium … msa – msa

Pingback:Numerical Problems on Vectors and equilibrium … msa – msa