Problem 12: Consider a ladder weighing 200 N resting against a smooth wall such that it makes an angle 600 with the horizontal. Find the reactions on the ladder due to the wall and ground.
of the ladder = AB = L
AC = CB
Weight of the
ladder = W = 200 N
Θ = 600
- Reaction of the wall
- Reaction of the ground
Reaction of the wall = R
force of the ground = F
F and horizontal = φ
apply 1st condition of equilibrium
condition of equilibrium with A as point of rotation, clockwise torque as
negative and anti-clockwise as positive,
consider the ∆AEB,
the values from (iv) and (v) in (iii)
As θ =
Magnitude of R
find the magnitude and direction of F, we use equations (i) and (ii)
the reaction of the ground on the ladder.
the angle of the reaction of the ground on the ladder.