**Problem 2**: Water is flowing smoothly through a closed pipe system. At one point the speed of water is 3 ms^{-1}, while at another point 3 meters higher the speed is 4 ms^{-1}. At the lower point, the pressure is 80 K Pa. Find the pressure at the upper point. Where 1 Nm^{-2} = 1 Pa.

**Solution**

**Given data** **At the upper point**

Speed of water = v_{1} = 4 ms^{-1}, (Relative) Height, h_{1} = 3 m

**At
the lower point**

Speed
of water = v_{2} = 3 ms^{-1}, Pressure
= P_{2} = 80 K Pa = 80000 Pa

Relative
height = h_{2} = 0 m

Required Pressure
at the higher point = P_{2} =?

**Formula ** For the smooth flow of water, the Bernoulli’s equation is

Put the values

Now we know that density of water is 1000 kg m^{-3} and the gravitational acceleration is 9.8 ms^{-2}. Therefore,

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