Menu Close

Problem 2: A cable has a length of 12 m and is stretched by 1.2 × 10-4 m when a stress of 8.0 × 108 Nm-2 is applied. What is the strain energy per unit volume in the cable when the stress is applied?

Solution

Given    Length of the cable, L = 12 m                     

Stretching in the cable, Δl = 1.2 × 10-4 m

 Stress applied = 8.0 × 108 Nm-2

Asked   Strain energy per unit volume, u

Formula               Strain energy per unit volume, u = ½ (stress × strain)

So we have to find strain first. Now

Put values

Now put the values of stress (given) and the strain (eq 1) in the formula,

 

3 Comments

  1. Pingback:Numerical Problems on Physics of Solids – msa

  2. Pingback:Numerical Problem 1, Physics of Solids – msa

  3. Pingback:Numerical Problem 3, Physics of Solids – msa

Leave a Reply

Your email address will not be published. Required fields are marked *