admin May 29, 2021 A cylindrical steel rod 0.50 m long and 1 cm radius is subjected to a tensile force of 1 × 104 N. 3 Comments Problem 3: A cylindrical steel rod 0.50 m long and 1 cm radius is subjected to a tensile force of 1 × 104 N. (a) What is the tensile stress? (b) What is tensile strain? (c) By what amount does the rod stretch? Solution Given Length of the rod, L = 0.50 mRadius of the rod, r = 1 cm = 1×10^{-2} mTensile force, F = 1 × 10^{4} N Required (a) Tensile stress (b) Tensile strain (c) Stretching, ΔL Formulae (i) Tensile stress = F/A (ii) Tensile strain = stress/K (iii) K = stress/strain (a) To find the tensile stress, we first find the cross-sectional area of the cylinder. We know,A = πr^{2}Put values, Now put the values in formula (i) (b) Now, for steel, the constant K = 200 mega pascals. Put in formula (ii) (c) Now consider formula (iii). We know that strain =ΔL/L. Put this in the formula Now put the values of K, L (from given) and stress (from equation 1), Next Question List of Question Previous Question Post navigation Previous Previous post: Numerical Problem 2, Physics of SolidsNext Next post: Numerical Problem 4, Physics of Solids 3 Comments Pingback:Numerical Problem 4, Physics of Solids – msa Pingback:Numerical Problem 2, Physics of Solids – msa Pingback:Numerical Problems on Physics of Solids – msa Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment Name * Email * Website Save my name, email, and website in this browser for the next time I comment.

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