Now given mass of Uranium = 1 kg

Molecular mass of Uranium = 285 u

Therefore, 235 kg of Uranium = 1 kilo mol

1 kg of Uranium = (1/235) kmol = 0.004255 kmol

Similarly, by Avogadro’s law, 1 kmol = 6.023 × 10^{26} atoms

⇒ 0.004255 kmol = 0.004255 × 6.023 × 10^{26 }= 0.025629 × 10^{26} atoms

Now energy released per event (atom) = 208 MeV

Energy released for 0.025629 × 10^{26} atoms = 208 × 0.025629 × 10^{26} =** 5.32 × 10**^{26} MeV

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