Problem 5: A proton is moving with a speed of 1 × 107 m/s, passes through a 0.020 cm thick sheet of paper and emerges with a speed of 2.0 × 106 ms-1. Assuming uniform deceleration, find retardation and time taken to pass through the paper.
Solution
Given: vi = 1 × 107 ms-1, Thickness = distance = s = 0.02 cm = 0.02 × 10-2 m,
vf = 2.0 × 106 ms-1
Find: Deceleration a and time t
To find the required quantities, we use equation of motion,
![](https://mashalscienceacademy.com/wp-content/uploads/2021/03/e30c3p11.png)
Put the values
![](https://mashalscienceacademy.com/wp-content/uploads/2021/03/e31c3p11.png)
This equation gives the deceleration of proton.
To find the time taken to pass through the paper, we use equation of motion vf = vi + at. Put values,
![](https://mashalscienceacademy.com/wp-content/uploads/2021/03/e32c3p11.png)
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