Menu Close

Problem 6: (a) Calculate the inductive reactance of a 3.00 mH inductor when 60.0 Hz and 10.0 kHz AC voltages are applied. (b) What is the rms current at each frequency if the applied rms voltage is 120 V.

Solution

(a) Given

Inductance, L= 3 mH = 3×10-3 H,
f1 = 60 Hz,
f2 = 10 kHz = 10 × 103 Hz

Asked

Inductive reactance in both XL1 and XL2

Formula

XL = 2πfL

Now put values for the first case, XL1 = 2πf1L = 2×3.14×60×3×10-3 = 1130.4 × 10-3 =1.13 Ω

Similarly, for second case, XL2 = 2πf2L = 2×3.14×10×103×3×10-3= 188.4 × 100=188 Ω

(b) Given

Vrms = 120 V,
XL1 = 1.13 Ω,
XL2 = 188 Ω

Find

Irms1, Irms2

Formula: Irms = Vrms/XL

Now put values for first case, Irms1 = 120/1.13 = 106 A

For the second case, Irms2 = 120/188 = 0.637 A

3 Comments

  1. Pingback:solved-numerical-problems-alternating-current-circuit-physics-12-msa – msa

  2. Pingback:Numerical Problem 7, Alternating Current Circuit, Physics 12 … msa – msa

  3. Pingback:Numerical Problem 5, Alternating Current Circuit, Physics 12 … msa – msa

Leave a Reply

Your email address will not be published. Required fields are marked *