Menu Close

Problem 7: For the same RLC series circuit having a 40.0 Ω resistor, 3.00 mH inductor and a 5.00 μF capacitor: (a) Find the resonant frequency (b) calculate Irms at resonance if Vrms is 120 V.

Solution

(a) Given

L = 3.0 mH = 3 × 10-3 H,
C = 5.0 μF = 5.0 × 10-6F

Asked

Resonant frequency, fr.

Formula

Put the values

(b) Given

R = 40 Ω
Vrms = 120 V

Asked: Irms

Formula

However in case of resonance, XL = XC, therefore, Z = R =40 Ω

Put the values

3 Comments

  1. Pingback:solved-numerical-problems-alternating-current-circuit-physics-12-msa – msa

  2. Pingback:Numerical Problem 6, Alternating Current Circuit, Physics 12 … msa – msa

  3. Pingback:Numerical Problem 8, Alternating Current Circuit, Physics 12 … msa – msa

Leave a Reply

Your email address will not be published. Required fields are marked *