Problem 6: Calculate the speed of efflux of kerosene oil from a narrow hole of a tank in which pressure is 4 * 10^-3 atm. Density of kerosene oil is 72 kg m-3. (one atmosphere = 1.03 * 105 pa).
Answer
Given data Pressure = 4 × 10-3 atm = 4 × 10-3 × 1.03 × 105 pa = 4.12 × 102 pa
Density of kerosene oil =0. 72 kg/m2
Required Speed of efflux = v =?
Formula Torricelli’s Theorem
![](https://mashalscienceacademy.com/wp-content/uploads/2021/07/c6p11numerical19.png)
Theory: Since we are not given with the height h of the tank, so to use the above formula we first find the height of the tank. As
![](https://mashalscienceacademy.com/wp-content/uploads/2021/07/c6p11numerical20.png)
Put the values from the given data
![](https://mashalscienceacademy.com/wp-content/uploads/2021/07/c6p11numerical21.png)
Put the values in the formula from the given data
![](https://mashalscienceacademy.com/wp-content/uploads/2021/07/numec9p12eq39.png)
This is the required velocity of efflux.
Velocity of efflux means the average flow rate of kerosene oil emitted from the tank in the atmosphere.
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