Given Heat given at constant pressure, ΔQp = 180 J
γ = 1.41
Required (i) Increase in the internal energy, ΔU
(ii) Work done by the ideal gas, ΔW
Formulae:
(2)
(3) ![](https://mashalscienceacademy.com/wp-content/uploads/2023/05/Thermodynamics-numerical-3-3.png)
Calculation: Divide (1) by (2),
![](https://mashalscienceacademy.com/wp-content/uploads/2023/05/Thermodynamics-3-5.png)
![](https://mashalscienceacademy.com/wp-content/uploads/2023/05/Thermodynamics-numerical-3-5.png)
Put values of ΔQp and γ from the given data,
![](https://mashalscienceacademy.com/wp-content/uploads/2023/05/Thermodynamics-numerical-3-6.png)
![](https://mashalscienceacademy.com/wp-content/uploads/2023/05/Thermodynamics-numerical-3-7.png)
To calculate the work done, apply first law with this value of Δu.
![](https://mashalscienceacademy.com/wp-content/uploads/2023/05/Thermodynamics-numerical-3-8.png)