admin January 6, 2022 Math's 12 Ex 2.1 Question 2 1 Comment Question 2: Use definition 2.1.1 to find out the average rate of change over the specified interval for the following functions: Solution a. s = 2t -3 from t = 2 to t = 5The average rate of change is given by,Let s(t) = 2t – 3, then s(t + Δt) = 2(t + Δt) – 3 Putting the values,Simplifying, b. y = x^{2} -6x +8 from x = 3 to x = 3.1Let y = f(x) = x^{2} -6x +8 ⇒ f(x + Δx) = (x+Δx)^{2} – 6(x+Δx) + 8Now rate of change is Substituting the values,Cancelling Δx,Now put x = 3, Δx = 3.1 – 3 = 0.1, we have c. A = πr^{2} from r = 2 to r = 2.1Let f(r) = πr^{2} ⇒ f(r+Δr) = π(r+Δr)^{2}. So the rate of change of A is,Simplifying,Now r = 2 and Δr = 2.1 – 2 = 0.1. Therefore, substituting in the above equation, d. Let Put t = 9, Δt = 16 – 9 = 7 Post navigation Previous Previous post: Math’s 12, Exercise 1.2, Question 1 … msaNext Next post: Math’s 12, Exercise 2.1, Question 3 1 Comment Pingback:Math’s 12, Exercise 2.1 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment Name * Email * Website Save my name, email, and website in this browser for the next time I comment.

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