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Problem 1: What is the magnitude of the force of attraction between an iron nucleus bearing charge q = +26e and its innermost electron, if the distance between them is 1.0 × 10-12m?

Solution

Given:

We know that charge on electron = e = 1.6×10-19C.
Since both an electron and a proton have charge of same magnitude but opposite sign, therefore, Charge on the 26 protons of the Iron nucleus = 26e= 26 × 1.6 × 10-19C.
Distance between the nucleus and innermost electron = r = 1 × 10-12m.

Required

Electrostatic force between the innermost electron and nucleus of Iron atom.

The electrostatic force between the nucleus and innermost electron can be found by Coulomb law.

Put the values

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