Problem 8: A coil of pure inductance 318 mH is
connected in series with a pure resistance of 75 ohms. The voltage across
resistor is 150 V and the frequency of power supply is 50 Hz. Calculate the
voltage of power source and the phase angle.

Solution

Given

Inductance, L = 318 mH = 0.318 H Resistance of resistor, R = 75 Ω
Voltage drop of resistor, V_{R} = 150 V Frequency of voltage, f = 50 Hz

Find: Voltage of the power source, V and phase angle ϕ.

Required

(1) Now to find V, we know the value of V_{R}. However, V_{L} needs to be calculated. For this purpose, we calculate the current which passes through the series circuit and the inductive reactance, X_{L}.

Now put the values in the formula, V_{L} = IX_{L},

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